What are the solutions to the equation z^3=(-1+sqrt(3)i) ?

The solutions to the equation z^3=(-1+sqrt(3)i) are

Find the zeros of z^3=(-1+sqrt(3)i)

The zeros of z^3=(-1+sqrt(3)i) are

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z^{3} = (- 1 + 3 i)

Solution steps

z^{3} = (- 1 + 3 i)

Remove parentheses:

(a) = a

z^{3} = - 1 + 3 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = - 1 + 3 i

∣ a ∣ = 2

ar g (a) = - \frac{π}{3} + π

Simplify

x^{3} + 6 x^{2} - x - 30 = 0

q^{3} - q^{2} - 30 q = 0

y, x y = x y

3 x + 1 + 4 x - 3 = 5 x + 4

- \frac{2}{3 x ^{\frac{1}{3}}} = 0

What are the solutions to the equation z^3=(-1+sqrt(3)i) ?
The solutions to the equation z^3=(-1+sqrt(3)i) are
Find the zeros of z^3=(-1+sqrt(3)i)
The zeros of z^3=(-1+sqrt(3)i) are