What is the answer to solvefor x,z=sqrt(x^2+y^2) ?

The answer to solvefor x,z=sqrt(x^2+y^2) is x=sqrt(z^2-y^2),x=-sqrt(z^2-y^2)

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solvefor x,z=sqrt(x^2+y^2)

solve for

x, z = x^{2} + y^{2}

x = z^{2} - y^{2}, x = - z^{2} - y^{2}

Solution steps

z = x^{2} + y^{2}

Square both sides:

z^{2} = x^{2} + y^{2}

z^{2} = x^{2} + y^{2}

Solve

z^{2} = x^{2} + y^{2} : x = z^{2} - y^{2}, x = - z^{2} - y^{2}

x = z^{2} - y^{2}, x = - z^{2} - y^{2}

3 x + 12 = x + 8

- x - 3 x = x - 15

- \frac{2}{3} x^{- \frac{1}{3}} = 0

a^{2} - x^{2}

x - 3 x = - 8 x + x + 8

What is the answer to solvefor x,z=sqrt(x^2+y^2) ?
The answer to solvefor x,z=sqrt(x^2+y^2) is x=sqrt(z^2-y^2),x=-sqrt(z^2-y^2)