What is the answer to sqrt(3x+3)-1=sqrt(8-2x) ?

The answer to sqrt(3x+3)-1=sqrt(8-2x) is x=2

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sqrt(3x+3)-1=sqrt(8-2x)

3 x + 3 - 1 = 8 - 2 x

x = 2

Solution steps

3 x + 3 - 1 = 8 - 2 x

Remove square roots

12 x + 12 = 25 x^{2} - 40 x + 16

Solve

12 x + 12 = 25 x^{2} - 40 x + 16 : x = 2, x = \frac{2}{25}

x = 2, x = \frac{2}{25}

Verify Solutions:

x = 2

True

, x = \frac{2}{25}

False

The solution is

x = 2

y, x^{\frac{2}{3}} + y^{\frac{2}{3}} = 1

1 - \frac{1}{3 x ^{\frac{2}{3}}} = 0

y, x = 4 - y^{2}

2 x - 6 - x - 5 = x - 1

2 x + 8 = 3 x - 2

What is the answer to sqrt(3x+3)-1=sqrt(8-2x) ?
The answer to sqrt(3x+3)-1=sqrt(8-2x) is x=2
Solve for x: sqrt(3x+3)-1=sqrt(8-2x)
The solution is x=2