What are the solutions to the equation (z+9)^2=-64 ?

The solutions to the equation (z+9)^2=-64 are z=8i-9,z=-8i-9

Find the zeros of (z+9)^2=-64

The zeros of (z+9)^2=-64 are z=8i-9,z=-8i-9

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(z + 9)^{2} = - 64

z = 8 i - 9, z = - 8 i - 9

Solution steps

(z + 9)^{2} = - 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 9 = - 64 : z = 8 i - 9

Solve

z + 9 = - - 64 : z = - 8 i - 9

The solutions to the quadratic equation are:

z = 8 i - 9, z = - 8 i - 9

3 (x^{2} - 8) - 6 = - 3

\frac{g}{2} + 6 = 14

(\frac{3}{y ^{3}})^{- 1}

2 (x + 5) - (x + 3) = - 7

\frac{4}{5} w - \frac{1}{2} = - 2 w + \frac{5}{2}

What are the solutions to the equation (z+9)^2=-64 ?
The solutions to the equation (z+9)^2=-64 are z=8i-9,z=-8i-9
Find the zeros of (z+9)^2=-64
The zeros of (z+9)^2=-64 are z=8i-9,z=-8i-9