What is the answer to sqrt(3x+1+\sqrt{x+2)}=3 ?

The answer to sqrt(3x+1+\sqrt{x+2)}=3 is x=2

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sqrt(3x+1+\sqrt{x+2)}=3

3 x + 1 + x + 2 = 3

x = 2

Solution steps

3 x + 1 + x + 2 = 3

Remove square roots

x + 2 = 9 x^{2} - 48 x + 64

Solve

x + 2 = 9 x^{2} - 48 x + 64 : x = \frac{31}{9}, x = 2

x = \frac{31}{9}, x = 2

Verify Solutions:

x = \frac{31}{9}

False

, x = 2

True

The solution is

x = 2

5 x + 39 + 6 = 8

2 x - 2 - 7 - 2 x = 1

7 x - 34 + 14 = 15

x + 12 = x + 6

9 x + 18 = x + 2

What is the answer to sqrt(3x+1+\sqrt{x+2)}=3 ?
The answer to sqrt(3x+1+\sqrt{x+2)}=3 is x=2
Solve for x: sqrt(3x+1+\sqrt{x+2)}=3
The solution is x=2