What is the answer to (-2x^2+4)/(sqrt(4-x^2))=0 ?

The answer to (-2x^2+4)/(sqrt(4-x^2))=0 is x=sqrt(2),x=-sqrt(2)

Solve for x: (-2x^2+4)/(sqrt(4-x^2))=0

The solution is x=sqrt(2),x=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{- 2 x ^{2} + 4}{4 - x ^{2}} = 0

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

\frac{- 2 x ^{2} + 4}{4 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 4 = 0

Solve

- 2 x^{2} + 4 = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

3 = x x

6 x + 24 = x + 4

- 3 + x + 59 = x

x - 11 = 0

x = - 70 + 17 x

What is the answer to (-2x^2+4)/(sqrt(4-x^2))=0 ?
The answer to (-2x^2+4)/(sqrt(4-x^2))=0 is x=sqrt(2),x=-sqrt(2)
Solve for x: (-2x^2+4)/(sqrt(4-x^2))=0
The solution is x=sqrt(2),x=-sqrt(2)