What is the answer to 2x^2-3x=2xsqrt(x^2-3x)+1 ?

The answer to 2x^2-3x=2xsqrt(x^2-3x)+1 is x=-1/5

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2x^2-3x=2xsqrt(x^2-3x)+1

2 x^{2} - 3 x = 2 x x^{2} - 3 x + 1

x = - \frac{1}{5}

Decimal Notation

x = - 0.2

Solution steps

2 x^{2} - 3 x = 2 x x^{2} - 3 x + 1

Remove square roots

4 x^{4} - 12 x^{3} + 5 x^{2} + 6 x + 1 = 4 x^{4} - 12 x^{3}

Solve

4 x^{4} - 12 x^{3} + 5 x^{2} + 6 x + 1 = 4 x^{4} - 12 x^{3} : x = - \frac{1}{5}, x = - 1

x = - \frac{1}{5}, x = - 1

Verify Solutions:

x = - \frac{1}{5}

True

, x = - 1

False

The solution is

x = - \frac{1}{5}

x^{\frac{1}{2}} - 9 x^{\frac{1}{4}} + 20 = 0

21 - 5 x = x - 3

x^{\frac{2}{3}} + 2 x^{\frac{1}{3}} - 3 = 0

x = 1 + x + 11

10 x + 50 = x + 5

What is the answer to 2x^2-3x=2xsqrt(x^2-3x)+1 ?
The answer to 2x^2-3x=2xsqrt(x^2-3x)+1 is x=-1/5
Solve for x: 2x^2-3x=2xsqrt(x^2-3x)+1
The solution is x=-1/5