What is the answer to sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x) ?

The answer to sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x) is x=-1

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sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x)

7 - 2 x - 5 + x = 4 + 3 x

x = - 1

Solution steps

7 - 2 x - 5 + x = 4 + 3 x

Remove square roots

140 - 12 x - 8 x^{2} = 16 x^{2} - 64 x + 64

Solve

140 - 12 x - 8 x^{2} = 16 x^{2} - 64 x + 64 : x = - 1, x = \frac{19}{6}

x = - 1, x = \frac{19}{6}

Verify Solutions:

x = - 1

True

, x = \frac{19}{6}

False

The solution is

x = - 1

x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} + 6 = 0

4 x - 15 = x - 3

2 4 x + 5 = 8 - x - 1

4 x + 4 - 2 = 4

16 x^{2} = 2 x

What is the answer to sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x) ?
The answer to sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x) is x=-1
Solve for x: sqrt(7-2x)-sqrt(5+x)=sqrt(4+3x)
The solution is x=-1