What is the answer to sqrt(2x+2)-sqrt(x-1)=2 ?

The answer to sqrt(2x+2)-sqrt(x-1)=2 is x=17,x=1

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sqrt(2x+2)-sqrt(x-1)=2

2 x + 2 - x - 1 = 2

x = 17, x = 1

Solution steps

2 x + 2 - x - 1 = 2

Remove square roots

x^{2} - 2 x + 1 = 16 x - 16

Solve

x^{2} - 2 x + 1 = 16 x - 16 : x = 17, x = 1

x = 17, x = 1

Verify Solutions:

x = 17

True

, x = 1

True

The solutions are

x = 17, x = 1

5 x + 56 - 3 = 1

x - 6 + 20 = 21

y, x y - 4 y^{2} = 12

- \frac{x}{4 - x ^{2}} = 0

x^{\frac{5}{3}} = 0

What is the answer to sqrt(2x+2)-sqrt(x-1)=2 ?
The answer to sqrt(2x+2)-sqrt(x-1)=2 is x=17,x=1
Solve for x: sqrt(2x+2)-sqrt(x-1)=2
The solution is x=17,x=1