What is the answer to solvefor y,x=sqrt(9-y^2) ?

The answer to solvefor y,x=sqrt(9-y^2) is y=sqrt(-x^2+9) {0<= x<= 3},y=-sqrt(-x^2+9) {0<= x<= 3}

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solvefor y,x=sqrt(9-y^2)

solve for

y, x = 9 - y^{2}

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

Solution steps

x = 9 - y^{2}

Square both sides:

x^{2} = 9 - y^{2}

x^{2} = 9 - y^{2}

Solve

x^{2} = 9 - y^{2} : y = - x^{2} + 9, y = - - x^{2} + 9

y = - x^{2} + 9, y = - - x^{2} + 9

Verify Solutions:

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

The solutions are

y = - x^{2} + 9 {0 \leq x \leq 3}, y = - - x^{2} + 9 {0 \leq x \leq 3}

y, x + y + 18 = 6 x + 6 y

3 x - 2 - x - 2 = 2

5 x + 66 + 2 = 8

3 x + 22 + 12 = 19

What is the answer to solvefor y,x=sqrt(9-y^2) ?
The answer to solvefor y,x=sqrt(9-y^2) is y=sqrt(-x^2+9) {0<= x<= 3},y=-sqrt(-x^2+9) {0<= x<= 3}