What is the answer to (-2x^2+16)/(sqrt(16-x^2))=0 ?

The answer to (-2x^2+16)/(sqrt(16-x^2))=0 is x=2sqrt(2),x=-2sqrt(2)

Solve for x: (-2x^2+16)/(sqrt(16-x^2))=0

The solution is x=2sqrt(2),x=-2sqrt(2)

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\frac{- 2 x ^{2} + 16}{16 - x ^{2}} = 0

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

\frac{- 2 x ^{2} + 16}{16 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 16 = 0

Solve

- 2 x^{2} + 16 = 0 : x = 22, x = - 22

x = 22, x = - 22

Verify Solutions:

x = 22

True

, x = - 22

True

The solutions are

x = 22, x = - 22

x + 4 = 5 - x - 1

5 x - 9 - x = - 1

x = 4 - x

x^{2} + a^{2}

5 x + 15 - 5 = 0

What is the answer to (-2x^2+16)/(sqrt(16-x^2))=0 ?
The answer to (-2x^2+16)/(sqrt(16-x^2))=0 is x=2sqrt(2),x=-2sqrt(2)
Solve for x: (-2x^2+16)/(sqrt(16-x^2))=0
The solution is x=2sqrt(2),x=-2sqrt(2)