What are the solutions to the equation (20+2x)(24+2x)=1292 ?

The solutions to the equation (20+2x)(24+2x)=1292 are x=7,x=-29

Find the zeros of (20+2x)(24+2x)=1292

The zeros of (20+2x)(24+2x)=1292 are x=7,x=-29

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(20 + 2 x) (24 + 2 x) = 1292

x = 7, x = - 29

Solution steps

(20 + 2 x) (24 + 2 x) = 1292

Expand

(20 + 2 x) (24 + 2 x) : 480 + 88 x + 4 x^{2}

480 + 88 x + 4 x^{2} = 1292

Move

1292

to the left side

4 x^{2} + 88 x - 812 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 88 \pm 8 8 ^{2} - 4 \cdot 4 ( - 812 )}{2 \cdot 4}

8 8^{2} - 4 \cdot 4 (- 812) = 144

x_{1, 2} = \frac{- 88 \pm 144}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 88 + 144}{2 \cdot 4}, x_{2} = \frac{- 88 - 144}{2 \cdot 4}

x = \frac{- 88 + 144}{2 \cdot 4} : 7

x = \frac{- 88 - 144}{2 \cdot 4} : - 29

The solutions to the quadratic equation are:

x = 7, x = - 29

2 x^{2} + 13 x + 20 = 0

2 x^{2} + 9 x + 7

y^{3} - 125

x^{2} (x + 5) \geq 84 x

3 m + 8 = - 5 m - 64

What are the solutions to the equation (20+2x)(24+2x)=1292 ?
The solutions to the equation (20+2x)(24+2x)=1292 are x=7,x=-29
Find the zeros of (20+2x)(24+2x)=1292
The zeros of (20+2x)(24+2x)=1292 are x=7,x=-29