What is the answer to sqrt(1+\sqrt{1+\sqrt{x)}}=2 ?

The answer to sqrt(1+\sqrt{1+\sqrt{x)}}=2 is x=64

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sqrt(1+\sqrt{1+\sqrt{x)}}=2

1 + 1 + x = 2

x = 64

Solution steps

1 + 1 + x = 2

Square both sides:

1 + 1 + x = 4

1 + 1 + x = 4

Move

1

to the right side

1 + x = 3

Square both sides:

1 + x = 9

1 + x = 9

Move

1

to the right side

x = 8

Square both sides:

x = 64

x = 64

Verify Solutions:

x = 64

True

The solution is

x = 64

x - 10 = 4 - 2 x - 24

5 x + 11 - 9 = - 8

8 x - 47 - 3 = 0

3 x + 1 - x + 8 = 1

57 - 3 x = x - 1

What is the answer to sqrt(1+\sqrt{1+\sqrt{x)}}=2 ?
The answer to sqrt(1+\sqrt{1+\sqrt{x)}}=2 is x=64
Solve for x: sqrt(1+\sqrt{1+\sqrt{x)}}=2
The solution is x=64