What is the answer to sqrt(\sqrt{2x-1)+sqrt(x+4)}=6 ?

The answer to sqrt(\sqrt{2x-1)+sqrt(x+4)}=6 is x=221

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sqrt(\sqrt{2x-1)+sqrt(x+4)}=6

2 x - 1 + x + 4 = 6

x = 221

Solution steps

2 x - 1 + x + 4 = 6

Remove square roots

x^{2} - 2602 x + 1692601 = 5184 x + 20736

Solve

x^{2} - 2602 x + 1692601 = 5184 x + 20736 : x = 7565, x = 221

x = 7565, x = 221

Verify Solutions:

x = 7565

False

, x = 221

True

The solution is

x = 221

x^{\frac{3}{5}} + 1 = 0

5 x + 56 - 16 = - 7

- 16 + 10 x = x

7 + - 5 + 21 x = 24

x^{\frac{1}{3}} + x^{\frac{1}{6}} - 2 = 0

What is the answer to sqrt(\sqrt{2x-1)+sqrt(x+4)}=6 ?
The answer to sqrt(\sqrt{2x-1)+sqrt(x+4)}=6 is x=221
Solve for x: sqrt(\sqrt{2x-1)+sqrt(x+4)}=6
The solution is x=221