What is the answer to sqrt(x)+\sqrt[3]{x}-12=0 ?

The answer to sqrt(x)+\sqrt[3]{x}-12=0 is x=64

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sqrt(x)+\sqrt[3]{x}-12=0

x = 64

Solution steps

Use the following exponent property

Rewrite the equation with

u^{\frac{3}{2}} + u - 12 = 0

Solve

u^{\frac{3}{2}} + u - 12 = 0 : u = 4

u = 4

Substitute back

solve for

x

Solve

x = 64

Verify Solutions:

x = 64

True

The solution is

x = 64

x + 6 - 2 x - 4 = 0

2 x - 1 + 4 = 7

2 x + 1 = x - 1

x + 20 = 9

x + 3 = 9

What is the answer to sqrt(x)+\sqrt[3]{x}-12=0 ?
The answer to sqrt(x)+\sqrt[3]{x}-12=0 is x=64
Solve for x: sqrt(x)+\sqrt[3]{x}-12=0
The solution is x=64