What is the answer to sqrt(x^2-7)=sqrt(-2x-6) ?

The answer to sqrt(x^2-7)=sqrt(-2x-6) is x=-1+sqrt(2),x=-1-sqrt(2)

Solve for x: sqrt(x^2-7)=sqrt(-2x-6)

The solution is x=-1+sqrt(2),x=-1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 7 = - 2 x - 6

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x^{2} - 7 = - 2 x - 6

Square both sides:

x^{2} - 7 = - 2 x - 6

x^{2} - 7 = - 2 x - 6

Solve

x^{2} - 7 = - 2 x - 6 : x = - 1 + 2, x = - 1 - 2

x = - 1 + 2, x = - 1 - 2

Verify Solutions:

x = - 1 + 2

True

, x = - 1 - 2

True

The solutions are

x = - 1 + 2, x = - 1 - 2

21 - 5 x = x - 5

6 x - 32 + 17 = 21

2 x - 11 = 5

k, T = 2 π \frac{m}{k}

2 x + 2 = 6

What is the answer to sqrt(x^2-7)=sqrt(-2x-6) ?
The answer to sqrt(x^2-7)=sqrt(-2x-6) is x=-1+sqrt(2),x=-1-sqrt(2)
Solve for x: sqrt(x^2-7)=sqrt(-2x-6)
The solution is x=-1+sqrt(2),x=-1-sqrt(2)