What is the answer to 6x-3/(sqrt(1-x^2))=0 ?

The answer to 6x-3/(sqrt(1-x^2))=0 is x= 1/(sqrt(2))

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6x-3/(sqrt(1-x^2))=0

6 x - \frac{3}{1 - x ^{2}} = 0

x = \frac{1}{2}

Decimal Notation

x = 0.70710 \dots

Solution steps

6 x - \frac{3}{1 - x ^{2}} = 0

Multiply both sides by

1 - x^{2}

6 x 1 - x^{2} - \frac{3}{1 - x ^{2}} 1 - x^{2} = 0 \cdot 1 - x^{2}

Simplify

6 1 - x^{2} x - 3 = 0

Remove square roots

36 x^{2} - 36 x^{4} = 9

Solve

36 x^{2} - 36 x^{4} = 9 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

False

The solution is

x = \frac{1}{2}

3 x + 4 - x - 4 = 2 x

x + 2 = 2 x - 3

5 x + 81 + 2 = 8

10 + a + 7 = 11

7 x + 30 = x + 6

What is the answer to 6x-3/(sqrt(1-x^2))=0 ?
The answer to 6x-3/(sqrt(1-x^2))=0 is x= 1/(sqrt(2))
Solve for x: 6x-3/(sqrt(1-x^2))=0
The solution is x= 1/(sqrt(2))