What are the solutions to the equation (1+0.25x)(x^1)-((-0.25x)(-1))=0 ?

The solutions to the equation (1+0.25x)(x^1)-((-0.25x)(-1))=0 are x=0,x=-3

Find the zeros of (1+0.25x)(x^1)-((-0.25x)(-1))=0

The zeros of (1+0.25x)(x^1)-((-0.25x)(-1))=0 are x=0,x=-3

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(1 + 0.25 x) (x^{1}) - ((- 0.25 x) (- 1)) = 0

x = 0, x = - 3

Solution steps

(1 + 0.25 x) (x^{1}) - ((- 0.25 x) (- 1)) = 0

Factor

(1 + 0.25 x) (x^{1}) - ((- 0.25 x) (- 1)) : x (0.25 x + 0.75)

x (0.25 x + 0.75) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 0.25 x + 0.75 = 0

Solve

0.25 x + 0.75 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

3 (x - 1) = - 3

m^{2} - 2 m - 8

\frac{9 x ^{4} y ^{3}}{3 x ^{10} y ^{7}}

∣ 5 x - 16 ∣ = 4

\frac{\frac{1}{5}}{- 3}

What are the solutions to the equation (1+0.25x)(x^1)-((-0.25x)(-1))=0 ?
The solutions to the equation (1+0.25x)(x^1)-((-0.25x)(-1))=0 are x=0,x=-3
Find the zeros of (1+0.25x)(x^1)-((-0.25x)(-1))=0
The zeros of (1+0.25x)(x^1)-((-0.25x)(-1))=0 are x=0,x=-3