What is the answer to sqrt(3x-5)+sqrt(x-1)=2 ?

The answer to sqrt(3x-5)+sqrt(x-1)=2 is x=2

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sqrt(3x-5)+sqrt(x-1)=2

3 x - 5 + x - 1 = 2

x = 2

Solution steps

3 x - 5 + x - 1 = 2

Remove square roots

4 x^{2} - 32 x + 64 = 16 x - 16

Solve

4 x^{2} - 32 x + 64 = 16 x - 16 : x = 10, x = 2

x = 10, x = 2

Verify Solutions:

x = 10

False

, x = 2

True

The solution is

x = 2

8 x - 17 = 1

x^{\frac{2}{3}} = \frac{1}{3}

2 x + 11 - 10 = 0

3 x + 5 = 2 + 3 x

\frac{- 20 x - 10}{9 x ^{\frac{4}{3}}} = 0

What is the answer to sqrt(3x-5)+sqrt(x-1)=2 ?
The answer to sqrt(3x-5)+sqrt(x-1)=2 is x=2
Solve for x: sqrt(3x-5)+sqrt(x-1)=2
The solution is x=2