What is the answer to (-2x^2+9)/(sqrt(9-x^2))=0 ?

The answer to (-2x^2+9)/(sqrt(9-x^2))=0 is x= 3/(sqrt(2)),x=-3/(sqrt(2))

Solve for x: (-2x^2+9)/(sqrt(9-x^2))=0

The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))

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\frac{- 2 x ^{2} + 9}{9 - x ^{2}} = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

\frac{- 2 x ^{2} + 9}{9 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 9 = 0

Solve

- 2 x^{2} + 9 = 0 : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

, x = - \frac{3}{2}

True

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}

(x + 5)^{\frac{4}{3}} - 10 = 6

2 x + 1 - 4 = - 1

y, x = y + 1

3 x + 46 - 2 = 3

x = 4 + 3 x - 2

What is the answer to (-2x^2+9)/(sqrt(9-x^2))=0 ?
The answer to (-2x^2+9)/(sqrt(9-x^2))=0 is x= 3/(sqrt(2)),x=-3/(sqrt(2))
Solve for x: (-2x^2+9)/(sqrt(9-x^2))=0
The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))