What is the answer to roots 2-sqrt(4-(x+1)^2) ?

The answer to roots 2-sqrt(4-(x+1)^2) is x=-1

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roots 2-sqrt(4-(x+1)^2)

roots

2 - 4 - (x + 1)^{2}

x = - 1

Solution steps

2 - 4 - (x + 1)^{2}

The roots are the intercepts with the x-axis

(y = 0)

2 - 4 - (x + 1)^{2} = 0

Move

2

to the right side

- 4 - (x + 1)^{2} = - 2

Square both sides:

- x^{2} - 2 x + 3 = 4

- x^{2} - 2 x + 3 = 4

Solve

- x^{2} - 2 x + 3 = 4 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

\frac{1}{1 - 5 x} = \frac{1}{6}

x - 2 + x - 4 = 2 x - 2

2 x - 2 - x - 5 + 1 = 0

x + 5 + 18 = 19

x + 3 - 3 x - 2 = 7

What is the answer to roots 2-sqrt(4-(x+1)^2) ?
The answer to roots 2-sqrt(4-(x+1)^2) is x=-1