What is the answer to 1/(sqrt(1-x^2))= pi/3 ?

The answer to 1/(sqrt(1-x^2))= pi/3 is x=(sqrt(-9+pi^2))/pi ,x=-(sqrt(-9+pi^2))/pi

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1/(sqrt(1-x^2))= pi/3

\frac{1}{1 - x ^{2}} = \frac{π}{3}

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

Decimal Notation

x = 0.29683 \dots, x = - 0.29683 \dots

Solution steps

\frac{1}{1 - x ^{2}} = \frac{π}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot 3 = 1 - x^{2} π

Switch sides

1 - x^{2} π = 1 \cdot 3

Multiply the numbers:

1 \cdot 3 = 3

1 - x^{2} π = 3

Divide both sides by

π

1 - x^{2} = \frac{3}{π}

Square both sides:

1 - x^{2} = \frac{9}{π ^{2}}

1 - x^{2} = \frac{9}{π ^{2}}

Solve

1 - x^{2} = \frac{9}{π ^{2}} : x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

Verify Solutions:

x = \frac{- 9 + π ^{2}}{π}

True

, x = - \frac{- 9 + π ^{2}}{π}

True

The solutions are

x = \frac{- 9 + π ^{2}}{π}, x = - \frac{- 9 + π ^{2}}{π}

g, v = 2 g h

x x - 8 = 3

18 x^{2} - 6 x + 1 = 3 x

14 x + 2 + 18 = 8

What is the answer to 1/(sqrt(1-x^2))= pi/3 ?
The answer to 1/(sqrt(1-x^2))= pi/3 is x=(sqrt(-9+pi^2))/pi ,x=-(sqrt(-9+pi^2))/pi