What are the solutions to the equation 12^2+b^2=13^2 ?

The solutions to the equation 12^2+b^2=13^2 are b=5,b=-5

Find the zeros of 12^2+b^2=13^2

The zeros of 12^2+b^2=13^2 are b=5,b=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2^{2} + b^{2} = 1 3^{2}

b = 5, b = - 5

Solution steps

1 2^{2} + b^{2} = 1 3^{2}

Move

1 2^{2}

to the right side

b^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 25, b = - 25

25 = 5

- 25 = - 5

b = 5, b = - 5

(- \frac{1}{3})^{- 4}

4 x + 7 (- x - 14) = - 164

\frac{3}{x} < 2

18 x^{2} + 12 x - 6

- 5 (- 7)

What are the solutions to the equation 12^2+b^2=13^2 ?
The solutions to the equation 12^2+b^2=13^2 are b=5,b=-5
Find the zeros of 12^2+b^2=13^2
The zeros of 12^2+b^2=13^2 are b=5,b=-5