What is the answer to solvefor y,xy=sqrt(x^2+y^2) ?

The answer to solvefor y,xy=sqrt(x^2+y^2) is y= x/(sqrt(x^2-1)) {x 1}

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solvefor y,xy=sqrt(x^2+y^2)

solve for

y, x y = x^{2} + y^{2}

y = \frac{x}{x ^{2} - 1} {x < - 1 or x > 1}

Solution steps

x y = x^{2} + y^{2}

Square both sides:

y^{2} x^{2} = x^{2} + y^{2}

y^{2} x^{2} = x^{2} + y^{2}

Solve

y^{2} x^{2} = x^{2} + y^{2} : y = \frac{x}{x ^{2} - 1}, y = - \frac{x}{x ^{2} - 1}

y = \frac{x}{x ^{2} - 1}, y = - \frac{x}{x ^{2} - 1}

Verify Solutions:

y = \frac{x}{x ^{2} - 1} {x < - 1 or x > 1}, y = - \frac{x}{x ^{2} - 1}

False

The solution is

y = \frac{x}{x ^{2} - 1} {x < - 1 or x > 1}

y, x + y + 2 = 2 x + 2 y

x - 3 = 4 x - 7

y, x + y = x y

What is the answer to solvefor y,xy=sqrt(x^2+y^2) ?
The answer to solvefor y,xy=sqrt(x^2+y^2) is y= x/(sqrt(x^2-1)) {x<-1\lor x>1}