What is the answer to 243=(17-4n)^{6/4} ?

The answer to 243=(17-4n)^{6/4} is n=-(27*3^{1/3}-17)/4

Solve for n: 243=(17-4n)^{6/4}

The solution is n=-(27*3^{1/3}-17)/4

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243 = (17 - 4 n)^{\frac{6}{4}}

n = - \frac{27 \cdot 3 ^{\frac{1}{3}} - 17}{4}

Decimal Notation

n = - 5.48518 \dots

Solution steps

243 = (17 - 4 n)^{\frac{6}{4}}

Take both sides of the equation to the power of

2 : 59049 = (17 - 4 n)^{3}

59049 = (17 - 4 n)^{3}

Solve

59049 = (17 - 4 n)^{3} : n = - \frac{27 \cdot 3 ^{\frac{1}{3}} - 17}{4}

n = - \frac{27 \cdot 3 ^{\frac{1}{3}} - 17}{4}

Verify Solutions:

n = - \frac{27 \cdot 3 ^{\frac{1}{3}} - 17}{4}

True

The solution is

n = - \frac{27 \cdot 3 ^{\frac{1}{3}} - 17}{4}

1 + 2 x + 7 = x - 3

x^{\frac{1}{2}} - 7 x^{\frac{1}{4}} + 12 = 0

5 3 x - 3 - 5 4 x - 7 = 0

1 - \frac{1}{3} x^{- \frac{2}{3}} = 0

y, 5 x y - 2 y - 3 x = 0

What is the answer to 243=(17-4n)^{6/4} ?
The answer to 243=(17-4n)^{6/4} is n=-(27*3^{1/3}-17)/4
Solve for n: 243=(17-4n)^{6/4}
The solution is n=-(27*3^{1/3}-17)/4