What is the answer to solvefor y,sqrt(x^2+y^2)=1 ?

The answer to solvefor y,sqrt(x^2+y^2)=1 is y=sqrt(1-x^2),y=-sqrt(1-x^2)

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solvefor y,sqrt(x^2+y^2)=1

solve for

y, x^{2} + y^{2} = 1

y = 1 - x^{2}, y = - 1 - x^{2}

Solution steps

x^{2} + y^{2} = 1

Square both sides:

x^{2} + y^{2} = 1

x^{2} + y^{2} = 1

Solve

x^{2} + y^{2} = 1 : y = 1 - x^{2}, y = - 1 - x^{2}

y = 1 - x^{2}, y = - 1 - x^{2}

Verify Solutions:

y = 1 - x^{2}

True

, y = - 1 - x^{2}

True

The solutions are

y = 1 - x^{2}, y = - 1 - x^{2}

x, x^{2} + y^{2} = r

\frac{4}{x} = 3 x - 2

9 x^{\frac{4}{3}} - 10 x^{\frac{2}{3}} + 1 = 0

(x^{2} + 1)^{2} = 5

x + x = 5

What is the answer to solvefor y,sqrt(x^2+y^2)=1 ?
The answer to solvefor y,sqrt(x^2+y^2)=1 is y=sqrt(1-x^2),y=-sqrt(1-x^2)