What is the answer to 2x-sqrt(6x+2)+1=0 ?

The answer to 2x-sqrt(6x+2)+1=0 is x=(1+sqrt(5))/4 ,x=(1-sqrt(5))/4

Solve for x: 2x-sqrt(6x+2)+1=0

The solution is x=(1+sqrt(5))/4 ,x=(1-sqrt(5))/4

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2 x - 6 x + 2 + 1 = 0

x = \frac{1 + 5}{4}, x = \frac{1 - 5}{4}

Decimal Notation

x = 0.80901 \dots, x = - 0.30901 \dots

Solution steps

2 x - 6 x + 2 + 1 = 0

Remove square roots

6 x + 2 = 4 x^{2} + 4 x + 1

Solve

6 x + 2 = 4 x^{2} + 4 x + 1 : x = \frac{1 + 5}{4}, x = \frac{1 - 5}{4}

x = \frac{1 + 5}{4}, x = \frac{1 - 5}{4}

Verify Solutions:

x = \frac{1 + 5}{4}

True

, x = \frac{1 - 5}{4}

True

The solutions are

x = \frac{1 + 5}{4}, x = \frac{1 - 5}{4}

x - 5 = 2 x - 6 - 2

6 x - 5 x - 6 = 0

f, f (x - 3) = x + 3 + 3

x - 1 = x - 9

x - 4 x - 1 = - 3

What is the answer to 2x-sqrt(6x+2)+1=0 ?
The answer to 2x-sqrt(6x+2)+1=0 is x=(1+sqrt(5))/4 ,x=(1-sqrt(5))/4
Solve for x: 2x-sqrt(6x+2)+1=0
The solution is x=(1+sqrt(5))/4 ,x=(1-sqrt(5))/4