What is the answer to \sqrt[3]{8x^3-1}=2x-1 ?

The answer to \sqrt[3]{8x^3-1}=2x-1 is x=0,x= 1/2

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\sqrt[3]{8x^3-1}=2x-1

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

Take both sides of the equation to the power of

3 : 8 x^{3} - 1 = 8 x^{3} - 12 x^{2} + 6 x - 1

8 x^{3} - 1 = 8 x^{3} - 12 x^{2} + 6 x - 1

Solve

8 x^{3} - 1 = 8 x^{3} - 12 x^{2} + 6 x - 1 : x = 0, x = \frac{1}{2}

x = 0, x = \frac{1}{2}

Verify Solutions:

x = 0

True

, x = \frac{1}{2}

True

The solutions are

x = 0, x = \frac{1}{2}

1 - x^{2} = - x

y, x = y^{\frac{2}{3}}

x + 78 = x + 6

What is the answer to \sqrt[3]{8x^3-1}=2x-1 ?
The answer to \sqrt[3]{8x^3-1}=2x-1 is x=0,x= 1/2
Solve for x: \sqrt[3]{8x^3-1}=2x-1
The solution is x=0,x= 1/2