What is the answer to (-2x^2+36)/(sqrt(36-x^2))=0 ?

The answer to (-2x^2+36)/(sqrt(36-x^2))=0 is x=3sqrt(2),x=-3sqrt(2)

Solve for x: (-2x^2+36)/(sqrt(36-x^2))=0

The solution is x=3sqrt(2),x=-3sqrt(2)

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\frac{- 2 x ^{2} + 36}{36 - x ^{2}} = 0

x = 32, x = - 32

Decimal Notation

x = 4.24264 \dots, x = - 4.24264 \dots

Solution steps

\frac{- 2 x ^{2} + 36}{36 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 36 = 0

Solve

- 2 x^{2} + 36 = 0 : x = 32, x = - 32

x = 32, x = - 32

Verify Solutions:

x = 32

True

, x = - 32

True

The solutions are

x = 32, x = - 32

10 - x + 5 = 7 x + 21

5 x + 5 = x + 1

x + 3 + 2 - x - x + 8 = 0

5 x = 40

5 x = 20

What is the answer to (-2x^2+36)/(sqrt(36-x^2))=0 ?
The answer to (-2x^2+36)/(sqrt(36-x^2))=0 is x=3sqrt(2),x=-3sqrt(2)
Solve for x: (-2x^2+36)/(sqrt(36-x^2))=0
The solution is x=3sqrt(2),x=-3sqrt(2)