What is the answer to sqrt(1-x)+sqrt(1+x)=1 ?

The answer to sqrt(1-x)+sqrt(1+x)=1 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(1-x)+sqrt(1+x)=1

The solution is No Solution for x\in\mathbb{R}

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1 - x + 1 + x = 1

No Solution for x \in R

Solution steps

1 - x + 1 + x = 1

Remove square roots

4 x^{2} + 4 x + 1 = 4 + 4 x

Solve

4 x^{2} + 4 x + 1 = 4 + 4 x : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

False

, x = - \frac{3}{2}

False

The solution is

No Solution for x \in R

10 + 10 x - 1 = 13

x - 8 + 5 = 7

x^{- \frac{1}{3}} - x^{\frac{2}{3}} = 0

4 x + 8 = 64

x + 5 = 11

What is the answer to sqrt(1-x)+sqrt(1+x)=1 ?
The answer to sqrt(1-x)+sqrt(1+x)=1 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(1-x)+sqrt(1+x)=1
The solution is No Solution for x\in\mathbb{R}