What is the answer to sqrt(x^2+3)=2x-1 ?

The answer to sqrt(x^2+3)=2x-1 is x=(2+sqrt(10))/3

Solve for x: sqrt(x^2+3)=2x-1

The solution is x=(2+sqrt(10))/3

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x^{2} + 3 = 2 x - 1

x = \frac{2 + 10}{3}

Decimal Notation

x = 1.72075 \dots

Solution steps

x^{2} + 3 = 2 x - 1

Square both sides:

x^{2} + 3 = 4 x^{2} - 4 x + 1

x^{2} + 3 = 4 x^{2} - 4 x + 1

Solve

x^{2} + 3 = 4 x^{2} - 4 x + 1 : x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

Verify Solutions:

x = \frac{2 + 10}{3}

True

, x = \frac{2 - 10}{3}

False

The solution is

x = \frac{2 + 10}{3}

x + x + x + x = 2

y - 8 + 5 = 7

0 = - 3 3 x + 1 + 2

x^{2} - 2 x + 3 - x = 3 - x + 8

3 - 2 v + 17 = 20

What is the answer to sqrt(x^2+3)=2x-1 ?
The answer to sqrt(x^2+3)=2x-1 is x=(2+sqrt(10))/3
Solve for x: sqrt(x^2+3)=2x-1
The solution is x=(2+sqrt(10))/3