What is the answer to -x/(sqrt(25-x^2))= 1/2 ?

The answer to -x/(sqrt(25-x^2))= 1/2 is x=-sqrt(5)

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-x/(sqrt(25-x^2))= 1/2

- \frac{x}{25 - x ^{2}} = \frac{1}{2}

x = - 5

Decimal Notation

x = - 2.23606 \dots

Solution steps

- \frac{x}{25 - x ^{2}} = \frac{1}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

- x \cdot 2 = 25 - x^{2} \cdot 1

Expand

25 - x^{2} \cdot 1 : 25 - x^{2}

- x \cdot 2 = 25 - x^{2}

Square both sides:

4 x^{2} = 25 - x^{2}

4 x^{2} = 25 - x^{2}

Solve

4 x^{2} = 25 - x^{2} : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

False

, x = - 5

True

The solution is

x = - 5

2 x + 7 + x = 8

x + 2 = 3 x + 6

x + 24 = 4 x + 1 - 1

x, p = \frac{a ^{3} m ^{6}}{2 x ^{4} y ^{7}}

What is the answer to -x/(sqrt(25-x^2))= 1/2 ?
The answer to -x/(sqrt(25-x^2))= 1/2 is x=-sqrt(5)
Solve for x: -x/(sqrt(25-x^2))= 1/2
The solution is x=-sqrt(5)