What is the answer to cube root of x+4}=\sqrt[3]{4x-5 ?

The answer to cube root of x+4}=\sqrt[3]{4x-5 is x=3

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cube root of x+4}=\sqrt[3]{4x-5

x = 3

Solution steps

Take both sides of the equation to the power of

3 : x + 4 = 4 x - 5

x + 4 = 4 x - 5

Solve

x + 4 = 4 x - 5 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

x + 4 = 1 + x - 3

x^{2} + 9 + 9 x^{2} + 25 = 18

9 = t^{2} - 16

n = (12 - n)^{\frac{1}{2}}

3 x + 2 = - 5

What is the answer to cube root of x+4}=\sqrt[3]{4x-5 ?
The answer to cube root of x+4}=\sqrt[3]{4x-5 is x=3
Solve for x: cube root of x+4}=\sqrt[3]{4x-5
The solution is x=3