What is the answer to \sqrt[4]{x^2-5}=2 ?

The answer to \sqrt[4]{x^2-5}=2 is x=sqrt(21),x=-sqrt(21)

Solve for x: \sqrt[4]{x^2-5}=2

The solution is x=sqrt(21),x=-sqrt(21)

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Popular >

x = 21, x = - 21

Decimal Notation

x = 4.58257 \dots, x = - 4.58257 \dots

Solution steps

Take both sides of the equation to the power of

4 : x^{2} - 5 = 16

x^{2} - 5 = 16

Solve

x^{2} - 5 = 16 : x = 21, x = - 21

x = 21, x = - 21

Verify Solutions:

x = 21

True

, x = - 21

True

The solutions are

x = 21, x = - 21

x = 2 x - 4 + 4

2 x - 3 = 1

5 x - 9 - 3 = x + 4 - 2

10 x^{5} = 3 x^{2}

x - 9 = 5

What is the answer to \sqrt[4]{x^2-5}=2 ?
The answer to \sqrt[4]{x^2-5}=2 is x=sqrt(21),x=-sqrt(21)
Solve for x: \sqrt[4]{x^2-5}=2
The solution is x=sqrt(21),x=-sqrt(21)