What is the answer to 0=(-2t^2+16)/(sqrt(16-t^2)) ?

The answer to 0=(-2t^2+16)/(sqrt(16-t^2)) is t=2sqrt(2),t=-2sqrt(2)

Solve for t: 0=(-2t^2+16)/(sqrt(16-t^2))

The solution is t=2sqrt(2),t=-2sqrt(2)

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0 = \frac{- 2 t ^{2} + 16}{16 - t ^{2}}

t = 22, t = - 22

Decimal Notation

t = 2.82842 \dots, t = - 2.82842 \dots

Solution steps

0 = \frac{- 2 t ^{2} + 16}{16 - t ^{2}}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = - 2 t^{2} + 16

Solve

0 = - 2 t^{2} + 16 : t = 22, t = - 22

t = 22, t = - 22

Verify Solutions:

t = 22

True

, t = - 22

True

The solutions are

t = 22, t = - 22

3 x - 1 + 9 = 8

4 + - 3 x + 10 = x

4 + 23 + 1 + x - 3 = 3

3 x + 4 - 1 = 2 x + 1

What is the answer to 0=(-2t^2+16)/(sqrt(16-t^2)) ?
The answer to 0=(-2t^2+16)/(sqrt(16-t^2)) is t=2sqrt(2),t=-2sqrt(2)
Solve for t: 0=(-2t^2+16)/(sqrt(16-t^2))
The solution is t=2sqrt(2),t=-2sqrt(2)