What is the answer to \sqrt[3]{x+28}-\sqrt[3]{x-28}=2 ?

The answer to \sqrt[3]{x+28}-\sqrt[3]{x-28}=2 is x=36,x=-36

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\sqrt[3]{x+28}-\sqrt[3]{x-28}=2

x = 36, x = - 36

Solution steps

Rewrite the equation with

and

x = u^{3} - 28

Solve

u = 4, u = - 2

Substitute back

solve for

x

Solve

x = 36, x = - 36

Verify Solutions:

x = 36

True

, x = - 36

True

The solutions are

x = 36, x = - 36

\frac{3 x + 4}{2 x + 2} = 0

x + 4 + 2 x - 6 = 11

\frac{1}{2 c} = \frac{1}{3}

3 x + 2 + 2 = 6 x

26 - 3 x = 5 x - 30

What is the answer to \sqrt[3]{x+28}-\sqrt[3]{x-28}=2 ?
The answer to \sqrt[3]{x+28}-\sqrt[3]{x-28}=2 is x=36,x=-36
Solve for x: \sqrt[3]{x+28}-\sqrt[3]{x-28}=2
The solution is x=36,x=-36