What is the answer to solvefor y,sqrt(xy)=12y-x ?

The answer to solvefor y,sqrt(xy)=12y-x is y= x/9 {x>= 0},y= x/(16) {x<= 0}

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solvefor y,sqrt(xy)=12y-x

solve for

y, x y = 12 y - x

y = \frac{x}{9} {x \geq 0}, y = \frac{x}{16} {x \leq 0}

Solution steps

x y = 12 y - x

Square both sides:

x y = 144 y^{2} - 24 y x + x^{2}

x y = 144 y^{2} - 24 y x + x^{2}

Solve

x y = 144 y^{2} - 24 y x + x^{2} : y = \frac{x}{9}, y = \frac{x}{16}

y = \frac{x}{9}, y = \frac{x}{16}

Verify Solutions:

y = \frac{x}{9} {x \geq 0}, y = \frac{x}{16} {x \leq 0}

The solutions are

y = \frac{x}{9} {x \geq 0}, y = \frac{x}{16} {x \leq 0}

8 x - 8 - 1 = x

7 + 3 x = 5 x + 4 + 5

x^{2} + 2 x + 1 = 5

\frac{x - a}{x - a}

x + x + 1 = 1

What is the answer to solvefor y,sqrt(xy)=12y-x ?
The answer to solvefor y,sqrt(xy)=12y-x is y= x/9 {x>= 0},y= x/(16) {x<= 0}