What is the answer to solvefor y,x^{1/2}+y^{1/2}=16 ?

The answer to solvefor y,x^{1/2}+y^{1/2}=16 is y=256-32x^{1/2}+x

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solvefor y,x^{1/2}+y^{1/2}=16

solve for

y, x^{\frac{1}{2}} + y^{\frac{1}{2}} = 16

y = 256 - 32 x^{\frac{1}{2}} + x

Solution steps

x^{\frac{1}{2}} + y^{\frac{1}{2}} = 16

Move

x^{\frac{1}{2}}

to the right side

y^{\frac{1}{2}} = 16 - x^{\frac{1}{2}}

Square both sides:

y = 256 - 32 x^{\frac{1}{2}} + x

y = 256 - 32 x^{\frac{1}{2}} + x

Verify Solutions:

y = 256 - 32 x^{\frac{1}{2}} + x

True

The solution is

y = 256 - 32 x^{\frac{1}{2}} + x

x - 1 = 7

x, \frac{( y ^{3} + y x ^{2} - 4 x )}{x + 1} = 0

x^{2} + 3 x + 5 = 3

y, x^{2} + y^{2} = 0

What is the answer to solvefor y,x^{1/2}+y^{1/2}=16 ?
The answer to solvefor y,x^{1/2}+y^{1/2}=16 is y=256-32x^{1/2}+x