What is the answer to sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0 ?

The answer to sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0 is x=3

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sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0

x + 1 - 2 x - 5 - x - 2 = 0

x = 3

Solution steps

x + 1 - 2 x - 5 - x - 2 = 0

Remove square roots

8 x^{2} - 12 x - 20 = 4 x^{2} - 8 x + 4

Solve

8 x^{2} - 12 x - 20 = 4 x^{2} - 8 x + 4 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

2 x^{\frac{5}{2}} - 7 = 23

\frac{5 x - 6}{3 x ^{\frac{1}{3}}} = 0

x x - a

x + 3 = 11 x + 5

\frac{2 x + 2}{4} = 3

What is the answer to sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0 ?
The answer to sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0 is x=3
Solve for x: sqrt(x+1)-sqrt(2x-5)-sqrt(x-2)=0
The solution is x=3