What is the answer to solvefor y,sqrt(9-x^2-y^2)=0 ?

The answer to solvefor y,sqrt(9-x^2-y^2)=0 is y=sqrt(-x^2+9),y=-sqrt(-x^2+9)

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solvefor y,sqrt(9-x^2-y^2)=0

solve for

y, 9 - x^{2} - y^{2} = 0

y = - x^{2} + 9, y = - - x^{2} + 9

Solution steps

9 - x^{2} - y^{2} = 0

Square both sides:

9 - x^{2} - y^{2} = 0

9 - x^{2} - y^{2} = 0

Solve

9 - x^{2} - y^{2} = 0 : y = - x^{2} + 9, y = - - x^{2} + 9

y = - x^{2} + 9, y = - - x^{2} + 9

Verify Solutions:

y = - x^{2} + 9

True

, y = - - x^{2} + 9

True

The solutions are

y = - x^{2} + 9, y = - - x^{2} + 9

y, x = 1 + y^{2}

x - 3 x^{\frac{1}{3}}

x - 7 - x = 7

\frac{1}{x} = x

\frac{- 2}{3 x ^{\frac{1}{3}}} = 0

What is the answer to solvefor y,sqrt(9-x^2-y^2)=0 ?
The answer to solvefor y,sqrt(9-x^2-y^2)=0 is y=sqrt(-x^2+9),y=-sqrt(-x^2+9)