What is the answer to solvefor L,f= 1/(2pisqrt(LC)) ?

The answer to solvefor L,f= 1/(2pisqrt(LC)) is L= 1/(4pi^2Cf^2)

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solvefor L,f= 1/(2pisqrt(LC))

solve for

L, f = \frac{1}{2 π L C}

L = \frac{1}{4 π ^{2} C f ^{2}}

Solution steps

f = \frac{1}{2 π L C}

Multiply both sides by

2 π L C

f \cdot 2 π L C = \frac{1}{2 π L C} \cdot 2 π L C

Simplify

f \cdot 2 π L C = 1

Divide both sides by

f \cdot 2 π

L C = \frac{1}{f \cdot 2 π}

Square both sides:

L C = \frac{1}{4 π ^{2} f ^{2}}

L C = \frac{1}{4 π ^{2} f ^{2}}

Solve

L C = \frac{1}{4 π ^{2} f ^{2}} : L = \frac{1}{4 π ^{2} C f ^{2}}

L = \frac{1}{4 π ^{2} C f ^{2}}

x = 5 x - 6

12 = 25 d

\frac{3 x + 14}{2 x + 7} = 0

1 + x + 4 = 3 x + 1

4 x - 3 \times 3 x - 5 = 3 x - 1

What is the answer to solvefor L,f= 1/(2pisqrt(LC)) ?
The answer to solvefor L,f= 1/(2pisqrt(LC)) is L= 1/(4pi^2Cf^2)