What is the answer to sqrt(x)+\sqrt[4]{x}=12 ?

The answer to sqrt(x)+\sqrt[4]{x}=12 is x=81

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sqrt(x)+\sqrt[4]{x}=12

x = 81

Solution steps

Use the following exponent property

Rewrite the equation with

u^{2} + u = 12

Solve

u^{2} + u = 12 : u = 3, u = - 4

u = 3, u = - 4

Substitute back

solve for

x

Solve

No Solution for

x \in R

x = 81

Verify Solutions:

x = 81

True

The solution is

x = 81

6 m - 38 = m - 5

y, (y + 1 - 1)^{2} - 2 = x

l, 40 = k^{0.5} l^{0.5}

7 = x - 1

(2 - x) (x + 2) = x

What is the answer to sqrt(x)+\sqrt[4]{x}=12 ?
The answer to sqrt(x)+\sqrt[4]{x}=12 is x=81
Solve for x: sqrt(x)+\sqrt[4]{x}=12
The solution is x=81