What is the answer to sqrt(x^2+3)+sqrt(2x-6)=11 ?

The answer to sqrt(x^2+3)+sqrt(2x-6)=11 is x\approx 7.73201…

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sqrt(x^2+3)+sqrt(2x-6)=11

x^{2} + 3 + 2 x - 6 = 11

x \approx 7.73201 \dots

Solution steps

x^{2} + 3 + 2 x - 6 = 11

Remove square roots

x^{4} - 4 x^{3} - 220 x^{2} + 448 x + 12544 = 968 x - 2904

Solve

x^{4} - 4 x^{3} - 220 x^{2} + 448 x + 12544 = 968 x - 2904 : x \approx 7.73201 \dots, x \approx 16.00694 \dots

x \approx 7.73201 \dots, x \approx 16.00694 \dots

Verify Solutions:

x \approx 7.73201 \dots

True

, x \approx 16.00694 \dots

False

The solution is

x \approx 7.73201 \dots

2 x = 17 x - 15

\frac{10}{9 x ^{\frac{1}{3}}} = 0

x + 3 = 12 x + 1

x + 8 - x = 2

4.3 = 1.5 h

What is the answer to sqrt(x^2+3)+sqrt(2x-6)=11 ?
The answer to sqrt(x^2+3)+sqrt(2x-6)=11 is x\approx 7.73201…
Solve for x: sqrt(x^2+3)+sqrt(2x-6)=11
The solution is x\approx 7.73201…