What is the answer to sqrt(x^2+2x+1)-sqrt(4x+1)=0 ?

The answer to sqrt(x^2+2x+1)-sqrt(4x+1)=0 is x=2,x=0

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sqrt(x^2+2x+1)-sqrt(4x+1)=0

x^{2} + 2 x + 1 - 4 x + 1 = 0

x = 2, x = 0

Solution steps

x^{2} + 2 x + 1 - 4 x + 1 = 0

Remove square roots

x^{2} + 2 x + 1 = 4 x + 1

Solve

x^{2} + 2 x + 1 = 4 x + 1 : x = 2, x = 0

x = 2, x = 0

Verify Solutions:

x = 2

True

, x = 0

True

The solutions are

x = 2, x = 0

5 x - 3 x + 8 = 8 x + 2

x - 4 x - 1 = 6

\frac{1}{2 x} - 2 = 0

4 + 5 v - 20 = v

- x^{3} - 4 x + 4 x + 1 = 0

What is the answer to sqrt(x^2+2x+1)-sqrt(4x+1)=0 ?
The answer to sqrt(x^2+2x+1)-sqrt(4x+1)=0 is x=2,x=0
Solve for x: sqrt(x^2+2x+1)-sqrt(4x+1)=0
The solution is x=2,x=0