What is the answer to 3x^2-3x-4sqrt(x^2-x+3)=6 ?

The answer to 3x^2-3x-4sqrt(x^2-x+3)=6 is x=-2,x=3

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3x^2-3x-4sqrt(x^2-x+3)=6

3 x^{2} - 3 x - 4 x^{2} - x + 3 = 6

x = - 2, x = 3

Solution steps

3 x^{2} - 3 x - 4 x^{2} - x + 3 = 6

Remove square roots

16 x^{2} - 16 x + 48 = 9 x^{4} - 18 x^{3} - 27 x^{2} + 36 x + 36

Solve

16 x^{2} - 16 x + 48 = 9 x^{4} - 18 x^{3} - 27 x^{2} + 36 x + 36 : x = - 2, x = 3, x = \frac{1}{3}, x = \frac{2}{3}

x = - 2, x = 3, x = \frac{1}{3}, x = \frac{2}{3}

Verify Solutions:

x = - 2

True

, x = 3

True

, x = \frac{1}{3}

False

, x = \frac{2}{3}

False

The solutions are

x = - 2, x = 3

- 41 z + 10 + z = 10

x + 5 - 9 = - 12

x + 3 = 5

What is the answer to 3x^2-3x-4sqrt(x^2-x+3)=6 ?
The answer to 3x^2-3x-4sqrt(x^2-x+3)=6 is x=-2,x=3
Solve for x: 3x^2-3x-4sqrt(x^2-x+3)=6
The solution is x=-2,x=3