What is the answer to sqrt(2y+1+y)-sqrt(2y+1-y)=2 ?

The answer to sqrt(2y+1+y)-sqrt(2y+1-y)=2 is y=8

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sqrt(2y+1+y)-sqrt(2y+1-y)=2

2 y + 1 + y - 2 y + 1 - y = 2

y = 8

Solution steps

2 y + 1 + y - 2 y + 1 - y = 2

Remove square roots

4 y^{2} - 16 y + 16 = 16 y + 16

Solve

4 y^{2} - 16 y + 16 = 16 y + 16 : y = 8, y = 0

y = 8, y = 0

Verify Solutions:

y = 8

True

, y = 0

False

The solution is

y = 8

x - 6 x^{\frac{1}{2}} + 4 = - 5

y, x = - 3 - 3 2 - 2 y + y^{2}

(x - 2)^{2} = 4

2 2 x = 4

3 - 2 x - 1 - x = 1

What is the answer to sqrt(2y+1+y)-sqrt(2y+1-y)=2 ?
The answer to sqrt(2y+1+y)-sqrt(2y+1-y)=2 is y=8
Solve for y: sqrt(2y+1+y)-sqrt(2y+1-y)=2
The solution is y=8