What is the answer to 2/(sqrt(1-x^2))=pi ?

The answer to 2/(sqrt(1-x^2))=pi is x=(sqrt(-4+pi^2))/pi ,x=-(sqrt(-4+pi^2))/pi

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2/(sqrt(1-x^2))=pi

\frac{2}{1 - x ^{2}} = π

x = \frac{- 4 + π ^{2}}{π}, x = - \frac{- 4 + π ^{2}}{π}

Decimal Notation

x = 0.77117 \dots, x = - 0.77117 \dots

Solution steps

\frac{2}{1 - x ^{2}} = π

Multiply both sides by

1 - x^{2}

\frac{2}{1 - x ^{2}} 1 - x^{2} = π 1 - x^{2}

Simplify

2 = π 1 - x^{2}

Switch sides

π 1 - x^{2} = 2

Divide both sides by

π

1 - x^{2} = \frac{2}{π}

Square both sides:

1 - x^{2} = \frac{4}{π ^{2}}

1 - x^{2} = \frac{4}{π ^{2}}

Solve

1 - x^{2} = \frac{4}{π ^{2}} : x = \frac{- 4 + π ^{2}}{π}, x = - \frac{- 4 + π ^{2}}{π}

x = \frac{- 4 + π ^{2}}{π}, x = - \frac{- 4 + π ^{2}}{π}

Verify Solutions:

x = \frac{- 4 + π ^{2}}{π}

True

, x = - \frac{- 4 + π ^{2}}{π}

True

The solutions are

x = \frac{- 4 + π ^{2}}{π}, x = - \frac{- 4 + π ^{2}}{π}

x + 2 + 9 = 0

x^{- \frac{2}{3}} - 4 = 0

x + 6 = x

5 x + 1 = 9

5 x + 5 = 4 x + 1

What is the answer to 2/(sqrt(1-x^2))=pi ?
The answer to 2/(sqrt(1-x^2))=pi is x=(sqrt(-4+pi^2))/pi ,x=-(sqrt(-4+pi^2))/pi