What is the answer to \sqrt[3]{x^2-1}+1=x ?

The answer to \sqrt[3]{x^2-1}+1=x is x=0,x=1,x=3

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\sqrt[3]{x^2-1}+1=x

x = 0, x = 1, x = 3

Solution steps

Remove roots

x^{2} - 1 = x^{3} - 3 x^{2} + 3 x - 1

Solve

x^{2} - 1 = x^{3} - 3 x^{2} + 3 x - 1 : x = 0, x = 1, x = 3

x = 0, x = 1, x = 3

Verify Solutions:

x = 0

True

, x = 1

True

, x = 3

True

The solutions are

x = 0, x = 1, x = 3

20.5 x + 4 - 41 = 0.02 x^{3} + 10.4

- 4 = - 8 + 32 - 2 n

56 - x = x

6 x = x

x - 4 = x + 8

What is the answer to \sqrt[3]{x^2-1}+1=x ?
The answer to \sqrt[3]{x^2-1}+1=x is x=0,x=1,x=3
Solve for x: \sqrt[3]{x^2-1}+1=x
The solution is x=0,x=1,x=3