What is the answer to sqrt(3-3x)-sqrt(3+x)=2 ?

The answer to sqrt(3-3x)-sqrt(3+x)=2 is x=-2

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sqrt(3-3x)-sqrt(3+x)=2

3 - 3 x - 3 + x = 2

x = - 2

Solution steps

3 - 3 x - 3 + x = 2

Remove square roots

16 x^{2} + 32 x + 16 = 48 + 16 x

Solve

16 x^{2} + 32 x + 16 = 48 + 16 x : x = 1, x = - 2

x = 1, x = - 2

Verify Solutions:

x = 1

False

, x = - 2

True

The solution is

x = - 2

2 x + 7 - x - 3 = 1

x^{\frac{2}{3}} - 3 x^{\frac{1}{3}} - 10 = 0

x + 10 = x + 4

2 x - 1 = x - 2

What is the answer to sqrt(3-3x)-sqrt(3+x)=2 ?
The answer to sqrt(3-3x)-sqrt(3+x)=2 is x=-2
Solve for x: sqrt(3-3x)-sqrt(3+x)=2
The solution is x=-2