What is the answer to 1+x/(sqrt(x^2-9))=0 ?

The answer to 1+x/(sqrt(x^2-9))=0 is No Solution for x\in\mathbb{R}

Solve for x: 1+x/(sqrt(x^2-9))=0

The solution is No Solution for x\in\mathbb{R}

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1 + \frac{x}{x ^{2} - 9} = 0

No Solution for x \in R

Solution steps

1 + \frac{x}{x ^{2} - 9} = 0

Multiply both sides by

x^{2} - 9

1 \cdot x^{2} - 9 + \frac{x}{x ^{2} - 9} x^{2} - 9 = 0 \cdot x^{2} - 9

Simplify

x^{2} - 9 + x = 0

Remove square roots

x^{2} - 9 = x^{2}

Solve

x^{2} - 9 = x^{2} :

No Solution

No Solution for x \in R

x - 4 - 3 = - 5

x - 1 + 1 = x + 4

2 x + 3 + 3 = 0

5 (6 x + 1)^{\frac{1}{4}} = 10

- 7 3 x - 5 = - 28

What is the answer to 1+x/(sqrt(x^2-9))=0 ?
The answer to 1+x/(sqrt(x^2-9))=0 is No Solution for x\in\mathbb{R}
Solve for x: 1+x/(sqrt(x^2-9))=0
The solution is No Solution for x\in\mathbb{R}